MnO2 + HCl = MnCl2 + Cl2 + H2O
If 1.92 mol of MnO2 and 96.4g of HCl react, determine the limiting reagent. Also determine the mass of Cl2 and the mass of unused reactant after the reaction.
The answer is provided in the image below
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment