Calculate the solubility of NiCO3 in moles per liter and grams per liter (Ksp = 1.4 x 10-7)
NiCO3 --> Ni2+ + CO32-
Since 1 formula unit of NiCO3 produces 2 ions, the formula for molar solubility (s) is
"K_{sp}=s^2"
Therefore,
"s=\\sqrt{K_{sp}}=\\sqrt{1.4\\times10^{-7}}=3.74\\times10^{-4}\\space{mol\/L}"
To find the solubility in grams per liter, s should be multiplied by the molar mass:
"3.74\\times10^{-4}\\frac{mol}{L}\\times118.7\\frac{g}{mol}=0.0444\\space{g\/L}"
Answer: "3.74\\times10^{-4}\\space{mol\/L}" ; 0.0444 g/L
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