(1)Methane
CH4=C(6)+4×H(1)=10e−
so the electron configurations of Methane is
σ1s2σ∗1s2σ2s2σ∗2s2[π2px1=π2py1]
(2) Methanol
CH3OH=C(6)+O(8)+4×H(1)=15e−
so the electron configurations of Methanol is
σ1s2σ∗1s2σ2s2σ∗2s2σ2pz2[π2px2=π2py2][π∗2px1]
(3) Chloromethane
CH3CL=C(6)+3×H(1)+CL(9)=16e−
so the electron configurations of Chloromethane is
σ1s2σ∗1s2σ2s2σ∗2s2σ2pz2[π2px2=π2py2][π∗2px1=π∗2py1]
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