13.7g "H_2O_2" in 100g solution
D=1.01 g/ml
"volume=\\frac{100}{1.01}=99 \\space ml"
moles of solute = "\\frac{13.7}{34}=0.4"
"molarity=\\frac{moles \\space of\\space solute} {v(L)}\\\\=\\frac{0.4}{0.099}\\\\=4.04"
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