13.7g H2O2H_2O_2H2O2 in 100g solution
D=1.01 g/ml
volume=1001.01=99 mlvolume=\frac{100}{1.01}=99 \space mlvolume=1.01100=99 ml
moles of solute = 13.734=0.4\frac{13.7}{34}=0.43413.7=0.4
molarity=moles of solutev(L)=0.40.099=4.04molarity=\frac{moles \space of\space solute} {v(L)}\\=\frac{0.4}{0.099}\\=4.04molarity=v(L)moles of solute=0.0990.4=4.04
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