Question #234389
An experiment to measure the enthalpy change for the reaction of aqueous copper(II) sulfate, CuSO4(aq) and zinc, Zn(s) was carried out in a coffee cup calorimeter as follows.
Cu 2+(aq) + Zn(s) → Cu(s) + Zn2+(aq) 50.0 cm3 of 1.00 mol dm–3 copper(II) sulfate solution was placed in a polystyrene cup and its average temperature after three readings was noted to be 25OC and the zinc powder was added . The final temperature was noted to be 91.5 OC. Calulate the heat of the reaction in kJ
1
Expert's answer
2021-09-07T23:28:31-0400

T=91.525=66.5°C∆T = 91.5 - 25 =66.5°C



Moles=1.00×50.01000=0.05moleMoles = 1.00×\frac{50.0}{1000}=0.05mole


Mass=159.609×0.05=7.98gramsMass= 159.609×0.05=7.98grams



Heat=4.18×7.98×66.5=2,218.2kJHeat = 4.18 × 7.98 × 66.5 =2,218.2kJ


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