Consider the reaction: NaNO3(s) + H2SO4(l) → NaHSO4(s) + HNO3(g) ΔH° = 21.2 kJ How much heat must absorbed by the reaction system to convert 100g of NaNO3 into NaHSO4(s)?
molar mass of NaNO3=85g / mol (23+14+48)
"mass\\space of \\space NaNO3\\space (from\\space balanced\\space equation)=1 \\times 85=85g"
since,15g of NaNO3 is converted =21.2 KJ absolute
"hence, \\space100g\\space of\\space NaNO3\\space converted = \\frac{100 \\times 21.1}{85}=24.9KJ"
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