Question #231447

how many grams of weak acid HF(molar mass=20.01g/mole) does it take to prepare 715mL of a solution that has PH=2.
075

Expert's answer

[H3O+]=10(pH)[H3O^+] = 10^{(-pH)}


[H3O+]=102=0.01M[H3O^+] = 10^{-2}=0.01M


Moles=Molarity×volumeMoles =Molarity ×volume


Moles=0.01×7151000=0.00715molesMoles =0.01×\frac{715}{1000}=0.00715moles


Mass=0.00715×20.01=0.14gramsMass=0.00715×20.01=0.14grams


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