[H3O+]=10(−pH)[H3O^+] = 10^{(-pH)}[H3O+]=10(−pH)
[H3O+]=10−2=0.01M[H3O^+] = 10^{-2}=0.01M[H3O+]=10−2=0.01M
Moles=Molarity×volumeMoles =Molarity ×volumeMoles=Molarity×volume
Moles=0.01×7151000=0.00715molesMoles =0.01×\frac{715}{1000}=0.00715molesMoles=0.01×1000715=0.00715moles
Mass=0.00715×20.01=0.14gramsMass=0.00715×20.01=0.14gramsMass=0.00715×20.01=0.14grams
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thanks for the assistance. it was really helpful of you
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thanks for the assistance. it was really helpful of you
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