A water sample is not alkaline to phenolphthalein. However, 100 mL of the sample on titration with 0.02 N HCl required 16.0 mL to obtain end point using methyl orange as indicator. What are the types and amount of alkalinity present in the sample?
H2SO4 is dibasic acid so N\50 = 0.02N
Molarity of acid = 0.02\2 = 0.01M
So mol of acid = 10mL × 0.01M
= 0.1mmol
So amount of base = 2×0.1 mmol = 0.2mmol
Conc of base = (0.2×10-3 mol × 1000)\100
=2×10-3 M
POH = -log[OH-] = -log (2×10-3) =2.7
PH + POH = 14
PH = 14 -POH = 14 -2.7 = 11.3
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