Question

You want to create a 0.25 M KCl solution using 5.00 grams of Potassium Chloride. How much water is needed?

Answer 1

Molar mass of KCl $= 74.5513 g/mol$

Moles of KCl $=\frac{0.25}{74.5513}=0.0034moles$

Volume of water needed $=\frac{0.0034}{0.25}=0.0134L$