A mineral contains 14.7% calcium and tungsten the remainder is oxygen find its emperical formula
Oxygen=67.5−14.7=52.8Oxygen = 67.5-14.7= 52.8Oxygen=67.5−14.7=52.8
Moles
calcium=14.740.08=0.367calcium =\frac{14.7}{40.08}=0.367calcium=40.0814.7=0.367
tungsten=67183.84=0.367tungsten =\frac{67}{183.84}=0.367tungsten=183.8467=0.367
Oxygen=52.832=1.65Oxygen =\frac{52.8}{32}=1.65Oxygen=3252.8=1.65
Mole ratio
Calcium=0.3670.367=1Calcium =\frac {0.367}{0.367}=1Calcium=0.3670.367=1
Tungsten=0.3670.367=1Tungsten =\frac {0.367}{0.367}=1Tungsten=0.3670.367=1
Oxygen=1.650.367=4.49=4Oxygen =\frac {1.65}{0.367}=4.49= 4Oxygen=0.3671.65=4.49=4
Empirical formula CaO4W
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