Question

What mass of silver nitrate (169.9g/mole) is needed to convert 2.33g of sodium carbonate (106.0g) to silver carbonate

Answer 1

Na₂CO₃ (aq) + 2 AgNO₃ (aq) → Ag₂CO₃ (s) + 2 NaNO₃ (aq)

$Moles =\frac{2.33}{106.0}=0.022moles$

Mass of $AgNO3= 0.022×169.9=3.7379moles$