Question

The absolute temperature of a gas at which 6.79 X 10 ^-2 moles occupies 164 mL at 893 torr. 

Answer 1

Volume of gas (V) = 164mL = 0.164 L

No of moles (n) = 6.79 × 10^-2 mol = 0.0679 mol

Pressure of gas (P) = 893 torr

Gas Constant(R)= 62.36 L.Torr/mol.K

By Ideal Gas law, PV = nRT

So, T = PV/nR =

893 × 0.164 / 0.0679 × 62.36

So, the Temperature of gas(T) = 34.587 K