Question

Find the molar concentration of the sulfuric acid from the titration result:

Complete the calculation given below:

No. of moles of KOH in 25.00 cm3

=





=

………………………… (1 mark)

\ no. of moles H2SO4 in 15.00 cm3

=





=

………………………… (1 mark)

\ molar concentration of H2SO4

=



(Include units in your answer)

=

………………………… (2 marks)

Answer 1

Relative Molecular Mass (RMM) of

KOH is 56.11 g/mole

No. of moles of KOH in 25.00 cm3$= \frac{0.95}{56.11}=0.0169moles$

2KOH (aq) + H₂SO₄ (aq) → K₂SO₄ (aq) + 2H₂O (l)

Moles of $H_2SO_4$ $=\frac{0.0169}{2}=0.00845moles$

Molarity =$\frac{0.00845}{0.015}=0.563M$