(ii) Find the molar concentration of the sulfuric acid from the titration result:
Complete the calculation given below:
No. of moles of KOH in 25.00 cm3 =
= ………………………… (1 mark)
no. of moles H2SO4 in 15.00 cm3 =
= ………………………… (1 mark)
molar concentration of H2SO4 =
(Include units in your answer) = ………………………… (2 marks)
(Total 10 marks)
1
Expert's answer
2021-07-17T04:44:54-0400
Relative Molecular Mass (RMM) of
KOH is 56.11 g/mole
No. of moles of KOH in 250 cm3"= \\frac{0.95}{56.11}=0.0169moles"
2KOH(aq) + H2SO4(aq) → K2SO4(aq) + 2H2O(l)
Moles of "H_2SO_4""=\\frac{0.0169}{2}=0.00845moles"
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