Question #21612
Sulphuric acid reacts with potassium to form potassium sulphate and hydrogen. Determine the mass of potassium sulphate produced if 6.0g of hydrogen wa also formed
Expert's answer
2K + H2SO4 = K2SO4 + H2
if m(H2) = 6 g, so
n(H2) = 6 g / 2 g/mol = 3 moles;
n(H2) : n(K2SO4) = 1 : 1;
n(K2SO4) = 3 moles;
m(K2SO4) = n(K2SO4) * M(K2SO4)
M(K2SO4) = 39*2 + 32 + 64 = 174 g/mol;
m(K2SO4) = 3 moles * 174 g/mol = 522g
if m(H2) = 6 g, so
n(H2) = 6 g / 2 g/mol = 3 moles;
n(H2) : n(K2SO4) = 1 : 1;
n(K2SO4) = 3 moles;
m(K2SO4) = n(K2SO4) * M(K2SO4)
M(K2SO4) = 39*2 + 32 + 64 = 174 g/mol;
m(K2SO4) = 3 moles * 174 g/mol = 522g
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
#339914 on Dec 2023
#339914 on Dec 2023