Mercury compounds are poisonous, but mercury ions can be removed from a solution by precipitating insoluble mercury (II) sulfide, HgS (s). Determine the minimum volume of 0.0783 mol/L sodium sulfide, Na2S (aq), that is needed to precipitate all the mercury ions in 75.5 mL of 0.100 mol/L, Hg(NO3)2 (aq).
1
Expert's answer
2013-01-28T09:42:58-0500
There is the next equation for this process:
Hg(NO3)2 + Na2S --> HgS + 2Na(NO3)2
For answering this question you need to find amount of Hg(NO3)2 in the solution:
0.100 mol per 1 L x mol per 0.0755 L
x = 0.000755 mol
0.000755 mol of Hg(NO3)2 can react with 0.000755 mol of Na2S (from equation)
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment