A compound contains 12.8grams copper 6.4grams sulphur 12.8grams oxygen and 18grams of crystallisation find the simpless formulae of the compound
Divide the above with their molar mass
For
Copper=12.863.546=0.2Copper = \frac{12.8}{63.546}=0.2Copper=63.54612.8=0.2
Sulphur=6.432.065=0.2Sulphur = \frac{6.4}{32.065}=0.2Sulphur=32.0656.4=0.2
Oxygen=12.815.999=0.8Oxygen = \frac{12.8}{15.999}=0.8Oxygen=15.99912.8=0.8
Crystallisation=1818.01528=0.999Crystallisation = \frac{18}{18.01528}=0.999Crystallisation=18.0152818=0.999
Ratio
0.20.2=1,0.20.2=1,0.80.2=4,1.00.2=5\frac{0.2}{0.2}=1, \frac{0.2}{0.2}=1, \frac{0.8}{0.2}=4, \frac{1.0}{0.2}=50.20.2=1,0.20.2=1,0.20.8=4,0.21.0=5
CuS4O25H2OCuS4O_25H_2OCuS4O25H2O
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment