Question #212446

When 2.35g of Magnesium (OH)2 is added to 250.0mL of water the temperature of water raises from 20.5°C to 36.0°C. What’s the molar enthalpy of the solution?


1
Expert's answer
2021-07-02T16:06:01-0400

Moles of Mg(OH)2 dissolved:


n=MassMolar mass=2.35g58.3197 g/mol=0.04 moln = \dfrac{Mass}{Molar\ mass} = \dfrac{2.35g}{58.3197\ g/mol} = 0.04\ mol


Heat released:

Q=mass of water  water specific heat capacity  temperature change=250g  4.18Jg  oC  (36.0 oC  20.5 oC)=16197.5JQ = mass\ of\ water\ *\ water\ specific\ heat\ capacity\ *\ temperature\ change = 250g\ *\ 4.18 \dfrac{J}{g\ *\ ^oC}\ *\ (36.0\ ^oC\ -\ 20.5\ ^oC) = 16197.5 J


Molar enthalpy of the solution:

ΔH=Heat releasedMoles of the solute=16197.5 J0.04 mol=404937.5 J/mol404.9kJmol\Delta H = -\dfrac{Heat\ released}{Moles\ of\ the\ solute} = -\dfrac{16197.5\ J}{0.04\ mol} = -404937.5\ J/mol \approx -404.9 \dfrac{kJ}{mol}


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