In the reaction
PC l3(g) +C l2(g) ⇋PC l5(g)
the Keq value at 300 K is 14.15. Initially, 0.81 mol PC l3 (g) and 1.37 mol C l2(g) are placed into 1.00 L container and allowed to reach equilibrium. What are the equilibrium concentrations of all these substances?
What two conditions are required, if we want to move reaction backward.
The solution of (i) part is given as:
In order to move the reaction forward,
1). Increase the concentration of product PCl5.
2). Reduce the reactant's concentration (PCl3 and Cl2)
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