Question

 In the reaction 

PC l3(g) +C l2(g) ⇋PC l5(g) 

the Keq value at 300 K is 14.15. Initially, 0.81 mol PC l3 (g) and 1.37 mol C l2(g) are placed into 1.00 L container and allowed to reach equilibrium. What are the equilibrium concentrations of all these substances?

What two conditions are required, if we want to move reaction backward.  

Answer 1

The solution of (i) part is given as:

In order to move the reaction forward,

1). Increase the concentration of product PCl₅.

2). Reduce the reactant's concentration (PCl₃ and Cl₂)