Question #19245
Zinc oxide, ZnO(s), is formed by the reaction of zinc sulphide, ZnS(s), with oxygen.
2ZnS(s) + 3O2(g) ---> 2ZnO(s) + 2SO2
If 16.7 g of zinc sulphide reacts with 6.70 g of oxygen, what mass of zinc oxide is produced?
2ZnS(s) + 3O2(g) ---> 2ZnO(s) + 2SO2
If 16.7 g of zinc sulphide reacts with 6.70 g of oxygen, what mass of zinc oxide is produced?
Expert's answer
n(ZnS) = 16.7 g / 97 g/mol = 0.172 mol
n(O2) = 6.7 g / 32 g/mol = 0.2 mol
n(ZnO) = 0.172 mol
m(ZnO) = 0.172 mol * 72 g/mol = 12.384 g
n(O2) = 6.7 g / 32 g/mol = 0.2 mol
n(ZnO) = 0.172 mol
m(ZnO) = 0.172 mol * 72 g/mol = 12.384 g
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