Answer to Question #192293 in Organic Chemistry for GHOST

Question #192293

a. A 25 cm3 sample of an aqueous solution of barium hydroxide, of concentration 0.146 mol dm3 was exactly neutralized by 28.7cm3 of aqueous nitric acid, according to the unbalanced equation:

Ba (OH)2 (aq) + HNO3(aq) ˗˗˗˗˗˗˗˗˃ Ba(NO3)2 (aq) + H2O (l)

i. Calculate the amount of nitric acid in terms molarity and in terms of number of moles 

ii. Differentiate molarity and number of moles.


1
Expert's answer
2021-05-12T06:40:08-0400

"Moles of Ba(OH)_2 =0.146\u00d7\\frac{25}{1000}=0.00365 mol"


"Moles of HNO_3=0.00365\u00d72=0.0073mol"


Molarity of HNO_3= "\\frac{0.0073}{28.7\u00d710^{-3}}=0.25MHNO \n\n_3"

​

The primary difference between the two comes down to mass versus volume. The molality describes the moles of a solute in relation to the mass of a solvent, while the molarity is concerned with the moles of a solute in relation to the volume of a solution.


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