Question

When 78.95 J of heat are added to 8.7 g of an unknown substance, it's temperature rises from 32.10°C to 33.95°C. What is the heat capacity constant of the unknown substance?

Answer 1

$q=mC\Delta T$

q=heat

$\Delta T$ =change in temperature =33.95-32.10=1.85 ^oC

m=mass

C=heat capacity constant

$C={q\over m \Delta T}$

$C={78.95\over 8.7×1.85}$

=$4.9 \ {J/\ g \ ^oC}$