Question #190450

How many grams of oxygen (O₂) react with 4.2 mol of iron (Fe) in the rusting reaction? 4Fe + 3O₂ ⟶ 2Fe₂O₃



1
Expert's answer
2021-05-09T00:00:46-0400

Moles of O2=3×4.24=O_2=\frac{3×4.2}{4}= 3.15


Mass of O2=32×3.15=100.8gramsO_2=32×3.15= 100.8grams



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