Answer to Question #189154 in Organic Chemistry for kira

Question

A 0.3126 g of oxalic acid, H₂C₂O_4, requires 26.1 ml of a particular concentration of NaOH(aq) to complete the following reaction. What is the molarity of the NaOH(aq)?

H₂C₂O₄(s) + NaOH(aq) → Na₂C₅O₄ (aq) + H_2O(I)

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Answer 1

Molar mass of H₂C₂O₄ = 90.03

Moles of H₂C₂O₄ $= \frac{0.3126}{90.03}=3.47×10^{-3}moles$

Balance equation

H₂C₂O₄ (aq) + 2 NaOH (aq) → Na₂C₂O₄ (aq) + 2 H₂O (l)

Moles of NaOH = $[3.47×10^{-3}]× 2=6.97×10^{-3} moles$

Molarity NaOH = $\frac{6.97×10^{-3}}{26.1×10^{-3}}=0.266M$