Answer to Question #188416 in Organic Chemistry for Ella

Question

A galvanic cell is constructed using the electrode based on the following half reactions:

Al3+(aq) + 3e-1 ---------> Al(s) -1.68 V

Mg2+(aq) + 2e-1 ---------> Mg(s) -2.37 V

(1) Write balance redox equation

(2) How many electrons are transferred?

(3) Write the cell notation

(4) Which is the anode?

(4) Which is the cathode?

(6) Which is the reducing agent?

(7) Which is the oxidizing agent?

Which substance is reduced?

Which substance is oxidized?

Calculate the cell potential

Answer 1

a) $3Mg(s) + 2Al^{3+} (aq) → 3Mg_2+(aq) + 2Al(s)$

b) 3 electrons

c) $Mg(s)|Mg2+(aq)||Al^{3+} |Ag(s)$

d) Anode =Mg

e) Cathode =Al