Question #187280

How many moles of Pb(NO₃)₂ are needed to produce 1790 grams of Pb₃P₂


1
Expert's answer
2021-05-03T07:55:58-0400

Moles=1790223.2=8.02molesMoles =\frac{1790}{223.2}=8.02 moles


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