In November 2024
Answer to Question #186764 in Organic Chemistry for Macaroni
The mass of calcium carbonate in a 0.125 g stick of chalk is determined by dissolving the chalk in 50.0 mL of 0.20 M HCl and then titrating any excess HCl with a standardized solution of KOH. A volume equal to 32.12 mL of 0.250 M KOH is required to reach the endpoint.
A) How many millimoles of the excess HCl was back-titrated?
Millimoles of the excess HCl was back-titrated=12.5 moles
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