What is the pH of 0.40M of H3PO4? Assume full dissociation.
"H_3PO_4 \u21cc H+ (aq) + H_2PO_4"
Ka = 7.2 x 10-3
After dissociation "H_3PO_4 \u21cc H+ (aq) + H_2PO_4"
"\\implies"
[H+] = 0.16
"P_H = - log[H^+]"
"P_H =0.79"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment