Why 1 bromo cyclopropene not follow morkovnikov,s rule when treated with HOCl
According to markovnikov's rule, if we add any polar compound to asymmetric alkene the negative part of additive reagent (in this case we have OH as negative part and Cl as positive part and HOCl as additive reagent) goes to the carbon having less number of hydrogen (in this case the second C in C3H3Br). This makes C3H3Br not to follow markovnikov's rule.
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