A radioisotope has an initial activity of 5 millicurie. 48hours later the observed activity is 4 millicurie. Determine
a) the half-life of the radioisotope
b) the initial number of nuclides in the radioisotope
1. Half life ;"48\u00d7\\frac {1} {24}=2" half lives.
2. The number of nuclei N as a function of time is N ;"N_0e\u2212\u03bbt," =32 nucleotides
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Please I don't understand
I don't understand, I did not see the workings that yielded the answers, will be happy to see how to solve it
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