Answer to Question #174341 in Organic Chemistry for Amoon

Question

Nitrogen dioxide NO2 gas and liquid water H2O react to form aqueous nitric acid HNO3 and nitrogen monoxide NO gas. Suppose you have 7.0 mol of NO2 and 13.0 mol of H2O in a reactor. Calculate the largest amount of HNO3 that could be produced. Round your answer to the nearest 0.1 mol.

Answer 1

$3NO_2 + H_2O\to 2HNO_3 + NO$

7 mol of NO₂ and 13 moles of H₂O

the limiting reagent is NO₂

3 moles of NO₂ = 2 moles of HNO₃

$\therefore$ 7 moles of NO₂ = 4.67 moles of HNO₃

This means that the largest amount of HNO₃ that can be produced is 4.7 moles (nearest 0.1 mol).