if 5% nacl solution use to regeneration of zeolite,it is capable to removing.....mg caco3 equivalent hardness per lit
If the efficiency is considered 100%, then
n(Na) = 0.0855 mol
n(Ca) = 0.0855 / 2 = 0.0428 mol
m(CaCO3) = 4.28 g = 4280 mg
Answer: 4280 mg.
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