Question #17002

Complete combustion of a 0.70-mol sample of a hydrocarbon, CxHy, gives 4.20 mol of CO2 and 3.50 mol of H20. The molecular formula of the original hydrocarbon is

Expert's answer


0.7 CxHy + xO2 =4.2CO2 + 3.5H2O /0.7

CxHy + x/0.7O2 =6CO2 +
5H2O


C6H10

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