Question

Determine the change in volume that takes place when 2.36 L sample of N2 (g) is heated from 250.0 k to 464.4 k

Answer 1

Initial Volume =2.36L

Initial Temperature =250.0K

Final Volume =?

Final Temperature =464.4K

According to Charles's Law ;

$V\alpha T$ ;$V=KT$

$\frac{V_1}{T_1}=\frac{T_2}{V_2}$

$V_2=\frac{T_2V_1}{T_1}$

$V_2=\frac{464.4×2.36}{250.0}$

$V_2=\frac{1095.984}{250}$

$V_2=4.38L$