Question #167995
What mass of sodium hydroxide can be made by reacting 2.3 grams of sodium with water
Expert's answer
2Na + 2H2O = 2NaOH + H2
n(NaOH) = n(Na) = (2.3 g)/(23 g/mol) = 0.1 mol
m(NaOH) = (0.1 mol)*(40 g/mol) = 4 grams
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