Question

Convert 15.33 grams of KCl to moles of KCI. Molar mass of KCl is 74.55 g/mol

Convert 29.14 grams of KCl to moles of KCI. Molar mass of KCl is 74.55g / mol 

Convert 44.33 grams of KCl to moles of LiF. Molar mass of LiF is 25.94 g / mol 

Convert 0.6047 moles of PCl5 to g of PCl5. Molar mass of PCl5 is 208.24 g / mol

Convert 0.8173 moles of BH3 to g of BH3. Molar mass of BH3 is 13.84 g / mol

Convert 0.8912 moles of BH3 to g of BH3. Molar mass of BH3 is 13.84 g / mol

Answer 1

a) $Molar Mass of KCL=74.55\frac{g}{mol}$

$=\frac{15.34g×mol of KCL} {74.55 g/mol}$

=0.2056moles of KCl

b) $Molar Mass of KCL=74.55\frac{g}{mol}$

$=\frac{29.14g×mol of KCL} {74.55g/mol}$

=0.3909 moles of KCl

c) $Molar Mass of LiF=25.94\frac{g}{mol}$

$=\frac{44.33g×mol of LiF } {25.94/mol}$

=1.7089moles of LiF

d) $Molar Mass of PCl5 =208.24\frac{g}{mol}$

$Grams of PCl5=0.6047 moles of PCl5 ×208.24g/mol$

=125.92g of $PCl_5$

e) $Molar Mass of BH3=13.84\frac{g}{mol}$

$=Grams of BH3=0.8173moles of BH3 ×13.84g/mol$

=11.31g of $BH_3$

f) $Molar Mass of BH3=13.84 \frac{g}{mol}$

$=Grams of BH3=0.8912moles of BH3 ×13.84g/mol$

=12.33 g of $BH_3$