Question #16693
What volume of .06892 M NaOH is required to react completely with 41.25-mLof .06053 M H2SO4?
Expert's answer
n of H2SO4 in 41.25 ml is equal to
0.06053 mol in 1000 ml
n of acid
=0.002497 mol
H2SO4 + 2NaOH=Na2SO4 + H2O
n of NaOH =2*n of H2SO4 =
0.004994 mol
0.004994 mol in x ml
0.06892 mol in 1000
ml
x=72.46 ml
0.06053 mol in 1000 ml
n of acid
=0.002497 mol
H2SO4 + 2NaOH=Na2SO4 + H2O
n of NaOH =2*n of H2SO4 =
0.004994 mol
0.004994 mol in x ml
0.06892 mol in 1000
ml
x=72.46 ml
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