A chemist adds 105.0mL of a 0.817mol/L sodium carbonate Na2CO3
solution to a reaction flask. Calculate the mass in grams of sodium carbonate the chemist has added to the flask. Round your answer to 3 significant digits. please show steps thank you
Molarity= 0.817mol/L
Volume= 105.0ml= 0.105L
Molar mass= 106g/mol
Now,
Molarity= moles of solute/Litres of solution
Moles= Molarity x Litres of solution
= 0.817 x 0.105= 0.086mol
Recall that;
Mole = mass/molar mass
Mass= mole x molar mass
Mass= 0.086 x 106 = 9.12g
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