A solution
of H2SO4 with a molal concentration of 8.010 m has a density of 1.354 g/mL. What is the
molar concentration of this solution?
To solve for the molarity, we follow the formula below:
C = n / V
We therefore need to solve for the moles of solute and liters of solution. We can do two steps for this problem:
1. Get the moles of solute from the molality.
2. Determine the volume of the solution using the given density.
For the first step, we can assume that we have 1 kg of the solution to simplify our calculation on the moles of solute. This gives us nH2SO4 = 8.010 (mol)
For the second step, we still use the same assumption for the calculation to be valid:
V = 1 / 1.354 = 0.73855 (L)
Using the values from steps 1 and 2, we have:
C = 8.010 / 0.73855 = 10.85 (M)
Answer: CH2SO4 = 10.85 M.
Comments
Thank you so much in other websites I just got the answers but not appropriate explanation how So thank u
Leave a comment