Balance the following reaction in a basic solution: I- + MnO42-- → MnO2 + I2
I- + MnO42- → MnO2 + I2 (basic solution)
2I- - 2e- → I2 (oxidation)
MnO42- + 2H2O + 2e- → MnO2 + 4OH- (reduction)
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2I- - 2e- + MnO42- + 2H2O + 2e- → I2 + MnO2 + 4OH-
2I- + MnO42- + 2H2O → I2 + MnO2 + 4OH-
Answer: 2I- + MnO42- + 2H2O → I2 + MnO2 + 4OH-
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