Question

Find the concentration of 12.6 mL of lithium hydroxide if 40.0 mL of 0.200 mol/L hydrobromic acid is required to neutralize it

Answer 1

The neutralization reaction is:

LiOH + HBr --> LiBr + H₂O

Reactants are in 1:1 molar ratio, therefore

$n(LiOH)=n(HBr)=0.200mol/L\times0.0400L=0.008mol$

$[LiOH]=\frac{0.008mol}{0.0126L}=0.635M$

Answer: 0.635 M