Answer to Question #150360 in Organic Chemistry for Zoie

Question

To make future dilutions easier, Kai wants to prepare a stock solution at the correct concentration such that he can take 25.0 mL of the stock solution to prepare 755 mL of his 0.75 M (NH4)2SO4 solution. What concentration should he make the stock solution? (The molar mass of (NH4)2SO4 is 132.14 g/mol).

Answer 1

(25 mL)*C(stock solution) = (755 mL)*(0.75M)

C(stock solution) = (755 mL)/(25 mL)*(0.75M) = 22.65M