How many grams of K2CrO4 will I get if I react 75g FeCr2O4?
FeCr2O4 + K2CO3 + O2 --> K2CrO4 + Fe2O3 + CO2
The balanced equation is
4FeCr2O4 + 8K2CO3 + 7O2 --> 8K2CrO4 + 2Fe2O3 + 8CO2
m(K2CrO4)=75g(FeCr2O4)×1mol(FeCr2O4)223.83g(FeCr2O4)×8mol(K2CrO4)4mol(FeCr2O4)×194.19g(K2CrO4)1mol(K2CrO4)=130gm(K_2CrO_4)=75g(FeCr_2O_4)\times\frac{1mol(FeCr_2O_4)}{223.83g(FeCr_2O_4)}\times\frac{8mol(K_2CrO_4)}{4mol(FeCr_2O_4)}\times\frac{194.19g(K_2CrO_4)}{1mol(K_2CrO_4)}=130gm(K2CrO4)=75g(FeCr2O4)×223.83g(FeCr2O4)1mol(FeCr2O4)×4mol(FeCr2O4)8mol(K2CrO4)×1mol(K2CrO4)194.19g(K2CrO4)=130g
Answer: 130 g
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