Question

A 0.299 g sample of a gas was held in a 0.220 L container at 25.0°C and its pressure
was determined to be 0.757 atm. What is the molar mass of the gas?

Answer 1

PV = nRT

PV = $\frac{w}{m}\times RT$

M = $\frac{wRT}{Pv}$

M= $\frac{0.299 \times 0.0821 \times 298}{0.757\times 0.22}$

M= 43.92 g/mol