Solution.
n(C6H6) = 0.032 mol
n(C6H6) = n(C6H5Cl) = 0.032 mol
m(C6H5Cl) = 3.6 g
"\\phi = \\frac{1.5}{3.6} \\times 100 \\% = 41.67 \\%"
m(HCl) = 1.168 g
m(HCl)prac = 0.49 g
Answer:
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