Solution.
n(C6H6) = 0.032 mol
n(C6H6) = n(C6H5Cl) = 0.032 mol
m(C6H5Cl) = 3.6 g
ϕ=1.53.6×100%=41.67%\phi = \frac{1.5}{3.6} \times 100 \% = 41.67 \%ϕ=3.61.5×100%=41.67%
m(HCl) = 1.168 g
m(HCl)prac = 0.49 g
Answer:
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