Answer to Question #145782 in Organic Chemistry for PATRICK

Question #145782
Calculate the enthalpy of the following chemical reaction: [6]
CS2(ℓ) + 3O2(g) → CO2(g) + 2SO2(g)
Given:
C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ/mol
S(s) + O2(g) → SO2(g) ΔH = -296.8 kJ/mol
C(s) + 2S(s) → CS2(ℓ) ΔH = +87.9 kJ/mol
1
Expert's answer
2020-11-23T06:53:13-0500

"\\Delta{H}_{reaction}=\\sum{\\Delta{H_{products}-\\sum\\Delta{H}_{reactants}}}=-393.5+2(-296.8)-87.9=-1075kJ\/mol"


Answer: -1075 kJ/mol


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