Answer to Question #145782 in Organic Chemistry for PATRICK

Question

Calculate the enthalpy of the following chemical reaction: [6]
CS2(ℓ) + 3O2(g) → CO2(g) + 2SO2(g)
Given:
C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ/mol
S(s) + O2(g) → SO2(g) ΔH = -296.8 kJ/mol
C(s) + 2S(s) → CS2(ℓ) ΔH = +87.9 kJ/mol

Answer 1

$\Delta{H}_{reaction}=\sum{\Delta{H_{products}-\sum\Delta{H}_{reactants}}}=-393.5+2(-296.8)-87.9=-1075kJ/mol$

Answer: -1075 kJ/mol