"\\begin{aligned}\n\u0394H &= n\u0394H\u02da\\\\\n\u0394H &= 1.55mol\\ CH_4 \u00d7 \\dfrac{-802kJ}{1mol\\ CH_4\\ in\\ rxn}\\\\\n\u0394H &= \u22121243.1kJ\n\\end{aligned}"
Note that the heat generated is negative because the reaction is exothermic and thus loses that amount of heat during combustion.
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