Question

35.93 ml of 0.166 M sodium hydroxide neutralizes 27.48 ml of sulfuric acid, what is the molar concentration of sulfuric acid

Answer 1

The equation for given reaction is:

2NaOH + H₂SO₄ --> Na₂SO₄ + 2H₂O

$n_{NaOH}=0.166M\times0.03593L=0.00596mol$

According to the equation, $n_{H_2SO_4}=\frac{1}{2}n_{NaOH}=0.00298mol$

Therefore, $c_{H_2SO_4}=\frac{0.00298mol}{0.02748L}=0.108M$

Answer: 0.108 M