pH midpoint = 7.4
a)
pH = - lg[H3O+], so:
[H3O+] = 10-pH = 10-7.4 = 4 * 10-8 mol/L
b)
[H3O+] * [OH-] = 10-14, so:
[OH-] = 10-14 / [H3O+] = 2.5 * 10-7 mol/L
c)
pOH = 14 - pH = 14 - 7.4 = 6.6
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment