Question

What is the theoretical yield (in grams) of C9H8O4 when 2.00 g C7H6O3 is heated
with 4.00 g of C4H6O3? If the actual yield is 1.98 g, what is the percent yield?
C7H6O3 + C4H6O3 → C9H8O4 + C2H4O2

Answer 1

C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + C₂H₄O₂

n of C₇H₆O₃ = 2/ (12*7 + 6 + 3*16) = 0.0145 moles this compound is less

n of C₄H₆O₃ = 4/(12*4 + 6+3*16) = 0.0392 moles

0.0145 0.0145
C₇H₆O₃ + C₄H₆O₃ → C₉H₈O₄ + C₂H₄O₂

1. m of C₉H₈O₄ = n* M_w = 0.0145* (12*9 + 8+ 16*4) = 2.61 g

2. w = 1.98/2.61*100% = 75.86%